(x+2)(x^2+3x-40)=0

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Solution for (x+2)(x^2+3x-40)=0 equation:


Simplifying
(x + 2)(x2 + 3x + -40) = 0

Reorder the terms:
(2 + x)(x2 + 3x + -40) = 0

Reorder the terms:
(2 + x)(-40 + 3x + x2) = 0

Multiply (2 + x) * (-40 + 3x + x2)
(2(-40 + 3x + x2) + x(-40 + 3x + x2)) = 0
((-40 * 2 + 3x * 2 + x2 * 2) + x(-40 + 3x + x2)) = 0
((-80 + 6x + 2x2) + x(-40 + 3x + x2)) = 0
(-80 + 6x + 2x2 + (-40 * x + 3x * x + x2 * x)) = 0
(-80 + 6x + 2x2 + (-40x + 3x2 + x3)) = 0

Reorder the terms:
(-80 + 6x + -40x + 2x2 + 3x2 + x3) = 0

Combine like terms: 6x + -40x = -34x
(-80 + -34x + 2x2 + 3x2 + x3) = 0

Combine like terms: 2x2 + 3x2 = 5x2
(-80 + -34x + 5x2 + x3) = 0

Solving
-80 + -34x + 5x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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